(4x+1)^2-4+7=9x^2+10+12x

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Solution for (4x+1)^2-4+7=9x^2+10+12x equation: 



(4x+1)^2-4+7=9x^2+10+12x

We move all terms to the left:

(4x+1)^2-4+7-(9x^2+10+12x)=0

We add all the numbers together, and all the variables

(4x+1)^2-(9x^2+10+12x)+3=0

We get rid of parentheses

-9x^2+(4x+1)^2-12x-10+3=0

We add all the numbers together, and all the variables

-9x^2-12x+(4x+1)^2-7=0

We move all terms containing x to the left, all other terms to the right

-9x^2-12x+(4x+1)^2=7

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